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Mathematics 17 Online
OpenStudy (anonymous):

solve x^2=180

OpenStudy (angela210793):

sqr both sides x=+-sqr180 x=+-sqr(36*5) x=+-6sqr5

OpenStudy (anonymous):

\[x^ 2 = 180\] \[x = \pm \sqrt{180}\] \[x = \pm 6\sqrt{5}\]

OpenStudy (anonymous):

\[\because x = \pm \sqrt{2\times2\times3\times3\times5}\] i.e \[x = \sqrt{4 \times9\times5}\] so \[x= 2\times3\sqrt{5}\] \[x=6\sqrt{5}\]

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