Question

if f(x)=the cubed root of (x-1), g(x)=x^2+1
what is g(f(x))?

Answer 1

f(x)=\[\sqrt[3]{x-1}\]
g(x)= \[x ^{2}+1\]

g(f(x)))=\[((\sqrt[3]{x-1})^2+1)\]

Answer 2

It is possible to simplify further