Question

∆ABC if BC is one inch longer AB, AC is 10 inches shorter than the sum of BC and and AB and the perimeter of ∆ABC is 72 inches find the length of BC

Answer 1

let AB be x
BC is one inch longer AB
so,BC = x+1
AC is 10 inches shorter than the sum of BC and and AB
so,AC = AB+BC-10
= x+x+1-10
perimeter=72
AB+BC+AC=72
x+x+1+x+x+1-10=72
4x-8=72
4x=80
x=80/4
x=20
BC=x+1
BC=20+1
BC=21