Question

Please help with quadratics: Solve x2 + 6x + 7 = 0

1) x = -1 and x = -5
2) 3±2√2
3) −3±2√2
4) −3±2√2/ 2

Answer 1

\[\left\{x\to -3-\sqrt{2},x\to -3+\sqrt{2}\right\} \]

Answer 2

Solve 3x2 + 4x = 2. (2 points)
Question 3 options:
1) 2 +or- √10 all over 6
2) -2 +or- √10 all over 3
3) -2 +or- √10 all over 3
4) -4 +or- √10 all over 3

Answer 3

Using Mathematica, the solution for 3x2 + 4x = 2 is:\[\left\{x\to \frac{1}{3} \left(-2-\sqrt{10}\right),x\to \frac{1}{3} \left(-2+\sqrt{10}\right)\right\} \]When the solutions are expanded the following is the case:\[\left\{x\to -\frac{2}{3}-\frac{\sqrt{10}}{3},x\to -\frac{2}{3}+\frac{\sqrt{10}}{3}\right\} \]2) and 3) of your option list are identical and are the same as the first solution of the solution list above.