Question

Pablo rolled a standard die 48 times. He got a 1 two times. How does this result compare to the expected results? Explain.

Answer 1

you "expect" one sixth of the rolls to be a 1, because the probability you get a 1 is 1/6
\[\frac{1}{6}\times 48=8\] so you would expect 8 ones, not 2

Answer 2

I would explain that Pablo got very lucky (or unlucky)