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Can someone help me with this question. I am really having problems with it. Graph the inequality on a plane 2x+3y<=6
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Solve the inequality in y<= mx+b form then graph the line with the slope m and the y intercept b, since y is less than or equal to this value you would have a solid line and your graph would be shaded below the line.
Another option is to find two points that fit on the line, and draw the line between them. An easy one is to set \(x=0\), plug it into the equation, and find the corresponding y value.
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