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Mathematics 16 Online
OpenStudy (travis):

3/(X^2+3X+2)>0

OpenStudy (anonymous):

x> -1 or x<-2

OpenStudy (travis):

thanks for the answer but how did you get the numerator off

OpenStudy (anonymous):

well.. the numerator is different than 0 so you can simply do: 1/(X^2+3X+2) > 0/3 1/(X+1) (X+2) >0

OpenStudy (anonymous):

understand now?

OpenStudy (travis):

yea thanks a lot!

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