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4(g-2)=2(g+8)
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solve for g?
\[4g-8=2g+16\] \[4g-2g=16+8\] \[2g=24\] \[g=\frac{24}{2}=12\]
4(g-2)=2(g+8) 2(g-2)=(g+8) 2g-4=g+8 g=12
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