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Write equation in standard form for a line crossing the x-axis at x=-3 and the y-axis at y=6
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you want the line between the points (-3,0) and (0,6) do you know how to find it?
slope is \[m=\frac{6-0}{0-(-3)}=\frac{6}{3}=2\]
and since y intercept is 6 you are done once you write \[y=2x+6\]
oh "standard form" might be \[2x-y+6=0\]
clear?
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