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25-3/7f=19+4/7f
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\[25-(3f/7)=19+(4f/7)\]
Try getting rid of the fractions first: \[25-\frac{3}{7}f = 19+\frac{4}{7}f\] Those 7s on the bottom of those fractions could be gotten rid of.
\[25-19=(4f+3f)/7\]
so its 6
yea :D
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thanks
always welcome :)
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