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find the area of a rectangle tennis court if the perimeter is 480 feet. the length of the court is 6 feet more than twice the width
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the width be 'x' and length be '2x+6' so, \[p = 2(l+b)\] \[2(x+2x+6)=480\]
\[3x+6=480/2\]
i dont get this
the answer is in the thousands
\[3x=240-6\] \[x=234/3\] \[x=78\] so,width=78 length=2(78)+6=162
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\[area of rectangle = l*w\]
just plug the values,thats all
nvm skip this one
whats your doubt ?
jus givin me a headache
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do you know perimeter of a rectangle formula ?
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