Question

Please help! At what value of x will the function g(x) have a hole?

g(x)=(x+5)(x-5)(x-3)
--------------
(x+5)(x+3)

Answer 1

-5

Answer 2

since you can cancel to get
\[\frac{(x-5)(x-3)}{x+3}\] but will still be undefined at -5