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OpenStudy (anonymous):
can some one check my answer please! Determine whether each situation involves a permutation or a combination.Then find the number of possibilities. selecting nine books to check out of the library from a reading list of twelve 9! permutation
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OpenStudy (dumbcow):
combination, you are picking a group of 9 books out of 12, order does not matter.
OpenStudy (dumbcow):
\[\frac{12!}{3!9!} = \frac{12*11*10}{3*2*1} = 2*11*10 = 220\]
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