Question

What is the equation of the line pretriceing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?

Answer 1

from point (-6,1),,, the slope perpendicular to y = –3x + 1 is +3 or m=1/3
using y=mx+b
1=(1/3)(-6)+b
1=-2+b
1+2=b
b=3 now
y=mx+b
y=(1/3)x+3 ans