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OpenStudy (anonymous):
the position vector of a particle is r(t) find the requested vector the velocity at t=2 for r(t)=(2t^2+5t+6)i-3t^3j+(10-t^2)k
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OpenStudy (anonymous):
r dot = (4t +5)i - 9t^2j -2tk At 2, 13i -36j-4k
OpenStudy (akshay_budhkar):
r dot is differential of r.. it you didn't get it.. and velocity is the differential of position vector of distance vector.. Though estudier has given you the answer :)
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