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Find the antiderivative of x/(x+2)^0.5
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http://www.wolframalpha.com/input/?i=x%2F%28x%2B2%29^0.5dx you can view the detailed answer.
x+2=a^2 dx=2a.da hence x/(x+2)^0.5.dx=a^2 - 2 2(a^2 - 2).da integrate and replace a by x ------- . 2a.da = a
strawbocide you get it?
Awesome, I get it now. Thanks
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