which one is the factor of 4u^4-16v^3 completely? A.4(u^2-2v)(u^2+2v) B.(2u-v)(2u+v)(u^2+v) C.(2u^2-4v)(2u^+4v) D.4(u^2-2v)(6^2-2v) i want to go with D but i think i am wrong

Question

which one is the factor of 4u^4-16v^3 completely? A.4(u^2-2v)(u^2+2v) B.(2u-v)(2u+v)(u^2+v) C.(2u^2-4v)(2u^+4v) D.4(u^2-2v)(6^2-2v)      i want to go with D but i think i am wrong

anonymous · Answer

Ok It must be C because I solved others and I am not getting answers from them

anonymous · Answer

ok

anonymous · Answer

THe answer is A

anonymous · Answer

oops its not a

jhonyy9 · Answer

yes can be A if there is 16y^2 and not 16y^3

anonymous · Answer

its none of them
unless you were looking for
$$4(u^2-2v)(u^2+2v)=4(u^4+2uv-2uv-4v^2)=4u^4-16v^2$$

anonymous · Answer

oops should be $$+2u^2v-2u^2v$$ in there

anonymous · Answer

It must be B sorry what I meant was B not C
Because only B has three v

anonymous · Answer

Solve it You will get your answer or Maybe something wrong in the Question