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Which is the completely factored form of 9x^2-36a^4 A.3(x^2-4a^4) B.9(x-2a^2)(x+2a^2) C.(3x-6a^2)(3x+6a^2) D.(3x-6a^2)^2 i dah went with a but it came out wrong
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This is a difference of squares (3x - 6a^2)(3x + 6a^2)
excuse mii spelling my computer are ackin stupid
When a quadratic has no "middle term" it's best to see if it is a difference of squares :)
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