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Give exact and approximate solutions to three decimal places y^2 -4+4=9 y=
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\[y^2 -4+4=9\]
-+3
I'm guessing this is supposed to be y^2 -4x+4=9 -< (y-2)^2 = 9 take square root
y^2-0y-9=0
solve the quadratic, get ur answer
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That's how to find the solution?
To repeat I'm guessing this is supposed to be y^2 -4x+4=9 (y-2)^2 = 9 take square root
y^2-4+4=9 -4+4=0 => y^2=9 y=root of 9 y=3
so it's 5, -1
Yes.
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to 3 decimal places....
I dont understand that part
me neither
lol
maybe I square each solution... idk
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