Question

Solve –2x^2 – 16x – 44 = 0
x=-8+_i sqrt 6
x=-8+_ 2i sqrt 6
x=-4+_ i sqrt 6
x=-4+_ 2i sqrt 6

Answer 1

–2x^2 – 16x – 44 = 0

x^2 + 8x + 22 = 0

(x + 4)^2 + 6 = 0

x + 4 = sqrt(-6) = plus minus i sqrt(6)

x = -4 plus minus i sqrt(6)