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need help with... 2u times 2u cubed times (vcubed) squared
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Does that mean \(2u \times 2u^3 \times (v^3)^2\)?
yea, and so what's the question?
(4u^4)(v^6)
when multiplying variables like u^3 and u^1 you add the 1 and the 3 to get 4 (V^3)(v^3)=V^3 squared add 3 and 3 to get 6
@Dalvoron yes it does & thanks guys ! i really apprieciate all the help!
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The general rules for combining powers in this case are \[x^a \times x^b = x^{a+b}\]\[(x^a)^b=x^{a \times b}\]
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