Question

Solve please:
W^4-12w^2-2=0
what is the solution
w=?
type an exact answer using radical as needed use commas to separate answers as needed.

Answer 1

Let
\[y=w^2\]
So
\[w^4-12w^2-2=0 \Leftrightarrow y^2-12y-2=0\]
Solve for y and you'll get two answers. I don't want to type the whole formula here, you should look it up, it's the quadratic formula.
The results are
\[y=6\pm \sqrt{48}\]
But\[w^2=y \Leftrightarrow w=\pm \sqrt{y} \Leftrightarrow w=\pm 6 \pm \sqrt{48}\ or\ w=\pm 6 \mp \sqrt{48}\]
So you get 4 roots.

Answer 2

Sorry I mean
\[w=\pm \sqrt{6\pm \sqrt{48}}\ or\ w=\pm \sqrt{6\mp \sqrt{48}}\]

Answer 3

Jazil, I can help you with you other question...

Answer 4

ok his answer is not right I need help with this one plse:\[w ^{4}-18w ^{2}-2=0\]

Answer 5

Oh

Answer 6

Okay, wait....

Answer 7

How is my answer not right?

Answer 8

We'll find out

Answer 9

it is 38 instead of 48

Answer 10

hero just work the one i just sent if you can

Answer 11

OH sorry I made a mistake when I copied it from my calc >.<

Answer 12

You'll have to come there so we can work on it together