Let D be a point on side BC of a triangle ABC. Let K,L be the circumferences of the sides ABC and ADC respectively. Prove that triangles ABC and AKL are similar.

Question

anonymous · Answer

im sorry. can u clarify something for me... is there a circle involved? cause u use the word circumference..

anonymous · Answer

Oh oops... I meant circumcentres.
And by sides ABC and ADC I meant triangles ABC and ADC

anonymous · Answer

ahaha... awesome

anonymous · Answer

im super weak at geometric proofs! o.O im interested in the solution when someone finds it.

anonymous · Answer

geometry is a very visual math so it's easier to understand it in person.let me draw it out first =X haha

anonymous · Answer

okay i think i get it

anonymous · Answer

Where is D?

anonymous · Answer

on side BC

anonymous · Answer

Blind, I am..

anonymous · Answer

Oooh, I will have to draw that....

anonymous · Answer

Hmm. won't let me upload pic?

anonymous · Answer

the problem is that im not so convinced theyre similar .. ..

anonymous · Answer

Yeah, okay, I'm stupid. It was pretty easy. Let's say angle ABD equals b. AKD should be 2b. Then KL bisects AKD so angle AKL equals b. Then repeat for other side.