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between which numbers is log base8 256? 0 and 1 1and 2 2 and 3 64 and 256
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2 and 3
how? solution pls.
\[8^2=64\] \[8^3=512\]
precisely. :D
thanks!
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anyway, if youre wondering how.. see this \[2 ^{8} = 256\] and \[2 ^{3} = 8\] when youre doing log base 8, youre doing log base 2^3 ie dividing by 3log2. get it?
i.e (8log2)/(3log2).. which gives 8/3. 3x2=6 &3x3=9. so 8/3 is more than 2 and less than 3.
thanks alot.. u guys gave me hope that i will never be a noob in math,! :D
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