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Which should you substitute as U when evaluating the integral of sin^4xcos^5xdx
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sinx=a
a^4 . (1-a^2)^2. da is the integral.
this is (a^6)/6 - (a^4)/4 + (a^2)/2 with a = sin x
i.e U=sin x
\[\sin ^4x (1-\sin^2x)^2cosxdx\]
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