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Write a quadratic equation having the given numbers as solutions. -5 and -2
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x=-5 or x=-2 x-(-5)=0 or x-(-2)=0 x+5=0 or x+2=0 (x+5)(x+2)=0 x^2+2x+5x+10=0 x^2+7x+10=0
(x+5)(x+2) = 0 has -5 and -2 as solutions right? Now just FOIL that out.
\[(x+5)(x+2)\] \[x ^{2}+7x+10\]
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