#include int main() { a=5; b=10; a=a+b-(b=a); printf(" a= %d b= %d",a,b); } this program is swapping of two variables... how does it work???

Question

#include<stdio.h>

int main()
{
a=5; 
    b=10; 
    a=a+b-(b=a); 
    printf("
a= %d  b=  %d",a,b);
}

this program is swapping of two variables... how does it work???

anonymous · Answer

look at the math.
a=5
b=10
then, the math does:
a=(5)+(10)-(10-5)=10
a->b=10

anonymous · Answer

working-
first your 'a' value will be stored in 'b' as yu had mention b=a which is assignment operator.....then a=a+b-(b=a) which makes 'a' value assigned with 'b'
tracing-
a=5
b=10
a=a+b-(b=a) 
a=5+10-(b=5)
a=15-5
a=10

hence a=10 and b=5