Question

can someone help me with the related rates?
questions:
the radius of the base of a right circular is decreasing at the rate of 4cm/min,and the height is increasing at the rate of 6cm/min. At what rate is the volume changing when the height is 12cm and the radius is 6cm?

Answer 1

circular what?????

Answer 2

right circular means cone

Answer 3

ok

Answer 4

any question bellz

Answer 5

dv/dt=(dv/dr)x(dr/dt)
i used chain rule

Answer 6

nope. the ans given is -120 π cm^3/min
hint: volume of cone = 1/3 π r^2 h

Answer 7

i knw

Answer 8

wait a sec

Answer 9

ok

Answer 10

this question is really a tough one

Answer 11

A solution using Mathematica 8 Home Edition with comments is attached.

Answer 12

ya... i really2 can't do it. really tough.

Answer 13

thanks robtobey!
4 helping me.. :)

Answer 14

Your welcome.

Answer 15

hashir,thanks 4 the help :)

Answer 16

Here's my setup for solving openstudy math problems with Mathematica.
(Didn't seem to post the first time)