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OpenStudy (anonymous):
factorize : 6a^2+a-12
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OpenStudy (aroub):
(2a+3)(3a-4)
OpenStudy (anonymous):
how did u solve it?
OpenStudy (anonymous):
After factoring it like aroub, take both terms and set them equal to 0. 2a+3=0 3a-4=0 Then solve for a in both of them. 2a+3=0 -> 2a=-3 -> a=-3/2 3a-4=0 -> 3a=4 -> a=4/3
OpenStudy (aroub):
oh nice way of factoring!! u know there is a plenty of ways to do it!!!!:D
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