Question

Find the average value of the function f(x) = (2x - 5)^2 on the interval [1, 2].

Answer 1

integrate, then divide by 1 which really just means integrate

Answer 2

\[\int_1^2(2x-5)^2dx\]

Answer 3

really? cool!

Answer 4

use a simple u-sub or just multiply out and integrate term by term

Answer 5

what "section" is this in? I don't remember this in integration...

Answer 6

answer is
\[\frac{13}{3}\]

Answer 7

HA! I just opened right to it! lol

Answer 8

approximate integration...

Answer 9

average value is integral divided by length of path

Answer 10

Length of x value? or hypotenuse

Answer 11

yea, length of straight path... anyway, thx