Question

Solve the following equation for x:

logx+log(x-1)=log(4x)

A. There are no solutions.
B. x = 0,5
C. x = 5
D. x = 1/4log(x - 1)

Answer 1

Combine the logs on the left using the property:
\[\log(a)+\log(b)=\log(ab)\]
\[\log(x(x-1))=\log(4x)\]
Raise everything by 10^(whatever)
\[x(x-1)=4x \rightarrow x^2-x=4x \rightarrow x^2-5x=0 \rightarrow x(x-5)=0\]
So x=0,5

Answer 2

Its only 5.
http://www.wolframalpha.com/input/?i=solve+log(x)%2Blog(x-1)%3Dlog(4x)

Answer 3

thanks!

Answer 4

No problemmmmmmm