Question

solve by completing the square

x^2 - 14x +3 = 0

Answer 1

now this makes sense
\[x^2-14x+3=0\]
\[x^2-14x=-3\]
\[(x-7)^2=-3+7^2\]
\[(x-7)^2=46\]
\[x-7=\pm\sqrt{46}\]
\[x=7\pm\sqrt{46}\]