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A tank contains 100 gal of brine made by dissolving 60 lb of salt in water. Salt water containing 1 lb of slat per gallon runs in at the rate of 2 gal/min and the well stirred mixture runs out at the same rate of 3 gal/min. Find the amount of salt in the tank after 30 minutes.
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y'=2-(3y/100) solve this differential eqn to get amount of salt(y) as a function of time. then find y(30)
Alright, hope it works :S
I solved it and I get y(x)=Ce^(-3x/100) + 200/3
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