Question

Find the critical number of y = x^2 + 2/x and find the points of extrema.

Answer 1

The critical points are when the derivative equals zero.

Answer 2

\[dy/dx = 2x - \frac{2}{x^{2}} = 0\]

Answer 3

is that the complete solution?

Answer 4

what do you mean?
the solution will list the critical points (x-values) and whether they are local minimums or maximums (y-values)

Answer 5

i set up the derivative for you..you have to solve for x, which will represent the point where the slope is zero and you have a local min or max depending on the concavity