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Mathematics 17 Online
OpenStudy (anonymous):

3/2 log9 - 2log6 ??

OpenStudy (anonymous):

-.1293...

OpenStudy (anonymous):

ah not for me ...

OpenStudy (anonymous):

just plugged into my calc :)

OpenStudy (anonymous):

but what is the method? and is the base 10??

OpenStudy (anonymous):

meant -.12493...

OpenStudy (angela210793):

base is 10 right so \[=\log[\sqrt{9^3}/6^2]=\log27/36\]

OpenStudy (anonymous):

wait, sorry, it doesn't need to be solved, just expressed as a single logarithm :P

OpenStudy (angela210793):

and idk log of tht no

OpenStudy (angela210793):

then my answer is right

OpenStudy (anonymous):

thank youu :)

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