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OpenStudy (anonymous):
evaluate:∫v dv/(6v²-1) again plz help me to solve this problem,,tnx
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OpenStudy (lalaly):
let u = 6v^2 -1 du=12vdv substituting 1/12∫du/u = 1/12 lnu substitute v again 1/12 ln(6v^2 -1)
OpenStudy (anonymous):
tnx
OpenStudy (lalaly):
:)
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