Question

Solve using the substitution method.

1/3x-1/5y= 7

1/6x+2/3= -4

Answer 1

can u show how u got that plz

Answer 2

Is the fraction (1/3)x or 1/(3x) ?

Answer 3

my answer is this but im missing Y
1/3x-1/5y= 7

1/6x+2/3= -4

y = (-15/2)/ (23/30)

y = -15(30)/2(23) = -15(15)/(23) = -225/23

Answer 4

I just need the right answer

Answer 5

i think its this
1/6x+2/3=-4
1/6x=-4-2/3
1/6x=-14/3
x=-28

substitute x=-28 into 1) 1/3(-28)-1/5y=7
-28/3+1/5y=7
1/5y=7+28/3
1/5y=49/3
y=245/3 or 81.666666666666666666666666666666...

Answer 6

umm