Question

solve for y

(y-7)/(y-1)=[(y-6)/(y-3)]+1

Answer 1

y = -3 or y =4

Answer 2

dam its not 6 and -2

Answer 3

\[\frac{y-7}{y-1} = \frac{y-6}{y-3}+1\]
combine right side into single fraction
\[\frac{y-7}{y-1} = \frac{y-6}{y-3}+\frac{y-3}{y-3} = \frac{2y-9}{y-3}\]
cross-multiply
\[(y-7)(y-3) = (2y-9)(y-1)\]
\[y^{2}-10y+21 = 2y^{2}-11y+9\]
combine like terms, set equal to zero
\[y^{2}-y-12 = 0\]
Factor
\[(y-4)(y+3)=0\]
y = 4, y = -3