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Fill in the blank to make the expression a perfect square. u^2-16u+?
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\[u^{2}-16u+?\]
divide -16 by 2 and square it.
its what you would do to complete the square, which regardless of what anyone tells you (satellite <.<), is a great technique!
\[(-\frac{16}{2})^2 = 64\] so: \[u^2-16u+ 64 \Rightarrow (u-8)^2\]
oya i remember now thanks
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