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OpenStudy (anonymous):
20b^2 -11b -3 = Factor completely...
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OpenStudy (anonymous):
I'm missing one critical step in these equations somewhere.. grrr...
OpenStudy (aroub):
(4b-3)(5b+1) <-- is that the answer u got??
OpenStudy (anonymous):
\[20b^2-15b+4b-3\] \[5b(4b-3)+1(4b-3)\] \[(5b+1)(4b-3)\]
OpenStudy (anonymous):
Tell me, how do you decide where to put the factors as in what order in the parenthesis? I end up with the correct factors but can't seem to put them in the right places....
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