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Please help! Add, subtract, multiply, or divide as indicated. Make sure that the final answer is simplified completely. 2/x-2*x^2-4/4
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order of addition- PEMDAS
\[\frac{2}{x-2}*\frac{x^{2}-4}{4}\]
factor x^2 -4
diff of 2 perfect squares
\[x^{2}-4 = ?\]
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-4
don't think number answer, you are factoring into (x+a)(x+b) form
a*b = -4 a+b = 0 what is a, what is b
any ideas? what are 2 numbers that multiply to -4
-4, 1?
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yep now check to see if they add up to 0
-3, so no.
so try 2 other numbers that multiply to -4
-2, 2
x-2/2?
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sorry i got cut off from my computer... so a and b are -2,2 \[x^{2}-4 = (x+2)(x-2)\] Now you can cancel and reduce
oh i see..almost the (x-2) is on the bottom so that is what cancels leaving (x+2) on top answer: (x+2)/2
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