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OpenStudy (anonymous):
0=1-sin(2πt) ; 0≤t≤2 solve for t
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OpenStudy (anonymous):
ouch,... t = 1/4, so that its sin(pi/2) = 1
OpenStudy (anonymous):
sin(0) = 0... not 1.
OpenStudy (anonymous):
so basically look for any values that make 2pi(t) = pi/2
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