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Factor by grouping: 4a(x-2)+3(2-x)=
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(x-2)(4a-3)
can you perhaps show me the steps so I can remember how to do these??? :)
if not, it's okay
The steps are the followings: We notice that if we'll factorize (2-x) by -1, we'll get: -(x-2) If you multiply (x-2) by -1, you'll get (2-x)
Then, you'll get the expression: 4a(x-2)-3(x-2) Now, the terms of the sum share the same factor (x-2) (x-2)(4a-3)
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