Question

State the center, vertices, foci and eccentricity of the ellipse with general
equation 16x2 + 25y2 = 400,

Answer 1

help me

Answer 2

What u need to do here is to divide through by 400

->x^2 /(400/16) + y^2 /(400/25) = 1

This is then an ellipse in standard position (centre at 0,0) with a, b equals the square roots of the denominators.