Question

the no of positive integral solution of abc=30
A) 30 B)27
C)8 D)none of these

Answer 1

1x1x30;2x3x5;10x3x1;2x15x1;5x6x1
therefore, total cases= 5x3=15

Answer 2

no the the result is another the result is 27 but i don't know how i get the answer

Answer 3

30 = 2*3*5 => 3! = 6 ways
30 = 1*1*30 => 3!/2! = 3 ways
30 = with just 1's => 3 *3c1*3 = 18 ways
total = 6+3+18 = 27 ways

Answer 4

Strange question, I would not have said myself that 2*3*5 and 2*5*3 were different solutions....