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If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 5x – 2y – z = 16 x + y + 4z = 6 3x + 2y + 6z = 16 Choices: A)–3y + 19z = –14 5y + 18z = –2 B)–7y – 21z = –14 –y – 6z = –2 C)7x + 7z = 28 x – 2z = 4 D)21x – 7y = 70 33x – 10y = 112
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