Question

y varies jointly with x and the square of n. When y = 25, x = 3 and n = 4. Find the value of y when x = 5 and n = 10. Round to the nearest whole number.

Answer 1

possible answers

260

320

360

290

Answer 2

y = kxn^2
this is a two step process:

plug in values of y,x and n
and solve for k
then insert value of k into the above formula

plug in x=5 and n=10
and solve for y

Answer 3

260

Answer 4

thanks ryan

Answer 5

y=kxn^2
25 = k(3)(4)^2
k=25/48

then

y=(25/48)(5)(10)^2

~260.416...