Question

all real values of x find them in 2/x+1=x-2/2? and if its to much to ask how do u work this out?

Answer 1

cross multiply
2*2 = (x+1)(x-2)
4=x^2 -2x +x -2
x^2-x -6 =0
(x-3)(x+2)=0
x=3 x=-2

Answer 2

(x-3)(x+2) = 0
x=3, x=-2

Answer 3

You can multiply up the bottom of each side so
\[2(2)=(x-2)(x+1)\]
which multiplied out will give you
\[4=x ^{2}-x-2\]
Rearranged
\[x ^{2}-x-6=0\]
Solved for x
x=3 x=-2

Answer 4

Thank u so much omg ive been at it for about 30 min omg thanks