Please! check my answer, TY
A die is rolled. Find each probability.
1. P(at least 5)=5,6
= (1/6)+(1/6)=2/6=1/3 ?
2. P(even or prime)
=P(2 or3 , 4 or 5, 5 or 6 )
=(1/6)+(1/6)+(1/6)+(1/6)+(1/6)=(5/6) ?

Question

Please! check my answer, TY
A die is rolled. Find each probability.
1. P(at least 5)=5,6 
   = (1/6)+(1/6)=2/6=1/3  ? 
2. P(even or prime)
 =P(2 or3 , 4 or 5,  5 or 6 )
=(1/6)+(1/6)+(1/6)+(1/6)+(1/6)=(5/6)  ?

anonymous · Answer

1. Correct

anonymous · Answer

1. is correct:)

anonymous · Answer

Not sure what question 2 is asking.

anonymous · Answer

If it's asking for probability that you're going to roll a prime or even number, then yeah I guess it's 5/6. Because 1 is the only one that doesn't fit those criteria (1 is not prime!)

anonymous · Answer

in 2.  prime 2,3,5 and even are 2,4,6
so common number are 2,3,4,5,6 
so  P(even or prime)= 5/6

anonymous · Answer

evn + prime = 5/6
than my answer is correct ?

anonymous · Answer

yes

anonymous · Answer

yes correct

anonymous · Answer

the question roll a die or tos a coin, some time:
(1/6)*(1/6)....
some time ( 1/6)+(1/6)...
I'm confusing how I know add or time?

zarkon · Answer

independent and 'and' you multiply

Mutually exclusive and 'or' you add

anonymous · Answer

good help ! thank Zakon