What are the x and y intercepts of the quadratic equation y= (x-3)^2 -25?

1) x: (-2,0) and (8,0)
y: (0,-16)

2) x: (2,0) and (-8,0)
y: (0,-16)

3) x: (-2,0) and (8,0)
y: (0,-25)

4) x: (2,0) and (-8,0)
y: (0,-25)

Question

What are the x and y intercepts of the quadratic equation y= (x-3)^2 -25?

1) x: (-2,0) and (8,0)
    y: (0,-16)

2) x: (2,0) and (-8,0)
    y: (0,-16)

3) x: (-2,0) and (8,0)
    y: (0,-25)

4) x: (2,0) and (-8,0)
    y: (0,-25)

anonymous · Answer

y intercept: put x = 0 and find y
you get $$y=(0-3)^2-25=9-25=-16$$

anonymous · Answer

x=8,-2, y=-16

anonymous · Answer

to find the x - intercept set y = 0 solve for x
you get 
$$(x-3)^2-25=0$$
$$(x-3)^2=25$$
$$x-3=5$$ or 
$$x-3=-5$$
$$x=8$$ or 
$$x=-2$$ so x - intercepts are 5 and -2

anonymous · Answer

sorry i mean of course 8 and -2